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2 answers:
The correct answers are A. and C.
The rate of from Table A can be calculated by finding the slope, which is
. Therefore, the slope is 
, which simplifies to 15.2.
The rate of Relationship B has to be more than 15.2. The slope of a line is the 'm' in the equation 'y=mx+b". In the answer choices, the 'm' values are 16.4, 14.9, 15.4, and 15.2. The only values that are greater than that are 15.4 and 16.4, so your answer is A and C.
The rate of from Table A can be calculated by finding the slope, which is
The rate of Relationship B has to be more than 15.2. The slope of a line is the 'm' in the equation 'y=mx+b". In the answer choices, the 'm' values are 16.4, 14.9, 15.4, and 15.2. The only values that are greater than that are 15.4 and 16.4, so your answer is A and C.
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*Select two choices: one for the centers and one for the spreads.
A. Centers: The sharks have a lower median age than the koi
B. Spreads: The ages of the koi are more spread out.
C. Centers: The sharks have a greater median age than the koi.
D. Spreads: The ages of the sharks are more spread out
(See attachement for diagram)
Answer:
A. and B.
Step-by-step explanation:
Measure of center that can be used in stating the differences between Koi and Shark is the median.
Examining the dot plot, the median age for Sharks is 20.
The median age for Koi is the 14th data point, which is 40.
Thus, for the center, we can conclude that Sharks has a lower median age than Koi.
For the spread, the larger the range, the more spread out the data are.
Thus:
Range for Sharks = 30 - 10 = 20
Range for Koi = 70 - 25 = 45
Therefore, we can conclude that the ages of Koi are more spread out.
