Let x be the length and y be the width2x + 2y = 40x + y = 20change that into y = mx + b formy= 20 – x
Area =xy = x (20-x) = 20x - x^2Area=-x^2+20xcomplete the square:Area=-(x^2 – 20x + 100) +100=-(x - 10)^2 + 100This is an calculation of a parabola that opens downward with vertex at (10,100), which means maximum area of 100 happens when x, the length=10)Dimensions of the rectangle with maximum area? 10 yds. by 10 yds., a square.
Answer:
70.
Step-by-step explanation:
Let x be the required number.
We are asked to find the number whose 90% equals to 63.
We can represent our given information in an equation as:
Now, we need to solve for x.
Therefore, 90% of 70 is 63.
You have to know that the graph of the arctangent function is a flat S-shaped curve that goes through (0, 0) and has asymptotes at ±π/2. The factor of 2 that multiplies it here expands it vertically so the asymptotes are at ±π. The +3 added to the x causes it to be shifted to the left by 3 units.
Answer:
x=16
Step-by-step explanation:
We are given that
we have to solve this equation for x
in order to do that we need to isolate x first
hence
subtracting 11 from both sides we get
Now we square on both sides we get
hence x =16
There are 156 rows of trees altogether.
<u>Step-by-step explanation:</u>
Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.
Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious.
Number of rows of Royal Gala=18
For 11 rows of red delicious,they plant 7 rows of yellow delicious.
Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.
For 66 rows of red delicious there would be
For 11 rows of red delicious,they plant 5 rows of Braeburn
for 1 row of red delicious,they would plant 5/11 rows of Braeburn.
For 11 rows of red delicious,they would plant
Total rows of trees=66+42+30+18=156