Answer:
true
Step-by-step explanation:
* substitute 30 for x *
we're left with 15 < 20 which is true
Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Three grams for one penny. three times eight (pennies)=24 grams
Answer:
75
Step-by-step explanation:
Average needed to get grade C = 70
Average = Total Amount / No of Items.
No of items = 4
therefore Total needed = 70 x 4 = 280
current total score = 66.75 + 66 + 72.25 = 205
the fourth test minimum score = 280 - 205 = 75
