Solve : 5x - 7y = 12 5y - 2x = - 7

2 answers:

6 0

5x - 7y = 12
<u>5y - 2x = -7</u>
5x - 7y = 12
<u>-2x + 5y = -7</u>
3x + 2y = 5
3(2) + 2(-1) = 5
6 + (-1) = 5
6 - 1 = 5
5 = 5

Afina-wow [57]2 years ago

3 0

There is one solution:

use elimination method

5x - 7y = 12
5y - 2x = -7 ---> change equation around

5x - 7y = 12
-2x + 5y = -7

2 x ( 5x - 7y) = 2 x (12) multiply both sides by 2
5 x (-2x +5y) = 5 x (-7)

this give you
10x - 14y =24
-10x+25y = -35 add down
-----------------------------
11y = - 11 x is eliminated to find y value

y = -1 input to one of the original equations

5(-1) - 2x = -7

-5 - 2x = -7
+5 +5 add 5 to both sides
----------------------------
-2x = -2
x = 1

your coordinates for when they intersect is at (1, -1)
one solution

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What are the intercept of 2X+3y= 6z=30

sattari [20]

The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).

<h3>What are the intercepts of the equation as give in the task content?</h3>

The x-intercept of the given equation can be determined by setting values of y and z to zero.

The y-intercept can be determined by setting x and z to zero.

While the z-intercept can be determined by setting x and y to zero.

Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.

Therefore, we have; (15,0,0)

The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)

And hence, the z-intercept is; z = 30/6 = 5.