The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Answer:
Q5. Option 1
Q7. Option 4
Step-by-step explanation:
Please see the attached pictures for full solution.
there are no graphs but the equation is y=3x-1
Answer:
C) I only
Step-by-step explanation:
( -1, -2) and (0,4)
Slope:
m=(y2-y1)/(x2-x1)
m=(4+2)/(0+1)
m=6/1
m=6
Slope-intercept:
y - y1 = m(x - x1)
y + 2 = 6(x + 1)
y + 2 = 6x + 6
y = 6x + 4
y - 16 = 6(x - 2)
y - 16 = 6x - 12
y = 6x + 4
X * (x + 10) = y - 40
(x + 2)(x + 12) = y
x^2 + 10x = x^2 + 14x + 24 - 40
10x = 14x - 16
-4x = -16
x = 4
4 + 10 = 14
The length of the original painting is 14 inches long.
