The correct answer to this question is C - Gravity is a force. Gravity
is also an example of a universal law. Well, according to Isaac Newton,
anyway. According to Newton's Law of Universal Gravitation, 'every point
mass attracts every single point mass by a force pointing along the
line intersecting both paths.'
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Answer:
54%
Explanation:
So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.
Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.
Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.
The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:
2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.
Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.
Thus, the total percentage of the period does the mass lie in these regions = 54%.
Answer:
i think its the second one
Explanation:
simply because hes living by that theory wveryday that because his dads a good athlete then hell be one too
Answer:
Acceleration up the ramp = -2.745 m/
Explanation:
Given
box is pulled at angle Θ =
Force applied F = 185N
coefficient of friction, μ = 0.27
mass of the box m = 35 kg
We know that,
acceleration due to gravity g = 9.8 m/
horizontal component = F cosΘ = 185 * cos =167.67
vertical component = F sinΘ =185*sin = 78.18
Another vertical component is due to gravity , force in given by
= mg
= 35 x 9.8
= 343.35 N
Normal force = -
= 343.35 - 78.18
= 265.17 N
Frictional force = * μ
= 265.17 * 0.27
= 71.596 N
To find acceleration, we know that,
force = mass x acceleration
acceleration =
Here force is the summation of frictional force and horizontal component of the applied force. These force act in opposite directions.
force = -
= 71.596 - 167.67
= -96.074
acceleration =
= -2.745 m/