Which pair of atoms has the highest electronegativity difference? Na-F Ca-F H-F C-F F-F

Chemistry

2 answers:

neonofarm [45]2 years ago

5 0

Answer: Na-F has the highest electronegativity difference.

Explanation: Electronegativity is the measure of how strongle an atom holds the electrons. The highest electronegative atom is Fluorine.

Electronegativity of Sodium = 0.93

Electronegativity of Calcium = 1

Electronegativity of Hydrogen = 2.1

Electronegativity of Carbon = 2.55

Electronegativity of Fluorine = 3.98

Electronegativity difference in the following compounds:

Electronegativity difference in Na-F = 3.98 - 0.93 = 3.05

Electronegativity difference in Ca-F = 3.98 - 1 = 2.98

Electronegativity difference in H-F = 3.98 - 2.1 = 1.88

Electronegativity difference in C-F = 3.98 - 2.55 = 1.43

Electronegativity difference in F-F = 3.98 - 3.98 = 0

From the above calculations, it is visible that the highest electronegativity difference is present in Na-F.

From all the compounds, it is clearly seen that sodium can loose the electrons easily and is most electropositive and fluorine is the most electronegative element.

babunello [35]2 years ago

3 0

The answer is Na-F. The F has highest electronegativity among these elements. So we need to find the element with smallest electronegativity. And this element is Na.

You might be interested in

According to the Lewis model of acids and bases, amines behave as bases in water because __________. View Available Hint(s) Acco

lyudmila [28]

Answer: the unshared pair of electrons on the nitrogen can accept a proton

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

Amines have a general molecular formula of $RNH_2$ which has lone pair of electrons on nitrogen and thus is able to donate electrons to a lewis acid which is short of electrons. In other words nitrogen can accept a proton.