Answer:
2:4
Step-by-step explanation:
I remember doing this is my class
K/3 + 4 -2k = -9k
First you add 9k to both sides
<span>k/3 + 4 -2k = -9k
</span> +9k +9k
<span>k/3 + 4 + 7k = 0
</span>
Now subtract 4 from both sides
k/3 + 4 + 7<span>k = 0
</span> -4 -4
k/3 + 7<span>k = -4
</span>
Now multiply 3 by both sides
k/3 + 7<span>k = -4
</span>x3 x3 x3
k +21k = -12
Now add k + 21k
22k = -12
Now divide both sides by 22
<span>22k = -12
</span>----- -----
22 22
k = -6/11
The base area is (pi)(r squared).
Answer:
1. Complex number.
2. Imaginary part of a complex number.
3. Real part of a complex number.
4. i
5. Multiplicative inverse.
6. Imaginary number.
7. Complex conjugate.
Step-by-step explanation:
1. <u><em>Complex number:</em></u> is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.
2. <u><em>Imaginary part of a complex number</em></u>: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.
3. <em><u>Real part of a complex number</u></em>: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.
4. <u><em>i:</em></u> a number defined with the property that 12 = -1.
5. <em><u>Multiplicative inverse</u></em>: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.
6. <em><u>Imaginary number</u></em>: any nonzero multiple of i; this is the same as the square root of any negative real number.
7. <em><u>Complex conjugate</u></em>: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.
Answer:
The indefinite integral
= ˣ ⁺ C
Step-by-step explanation:
x= 10sinθ
dx = 10cosθdθ
the step-to-step explanation is in the attachment