- What is the solution to the inequality -3x-42>3 ?
Add 42 to both sides.
Add 3 and 42 to get 45.
Divide both sides by -3. As -3 is <0, the inequality direction has changed.
Divide 45 by -3 to get -15.
16y = 164
y = 164 ÷ 16
y = 10.25
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Parallel lines need the same slope, and for y = 1/2x + 4, it is 1/2.
Let's solve for b.
2 = 1/2(-6) + b
2 = -3 + b
Add 3 on both sides.
5 = b
y = 1/2x + 5
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Answer:
6z^3 + 4z^2 + 5
Step-by-step explanation:
Combine like terms from each side of the expression.
(4z^3 + 2z^3) + (3z^2 + z^2) + (8 - 3)
6z^3 + 4z^2 + 5
