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3 years ago

16. A projectile is thrown directly upward at a velocity of 12.0 m/s. How long does it take for the

Mathematics

1 answer:

prisoha [69]3 years ago

8 0

It takes 1.22 s for the projectile to reach its maximum height ⇒ answer B

Step-by-step explanation:

The given is:

A projectile is thrown directly upward at a velocity of 12.0 m/s
Acceleration of gravity is g = 9.8 m/s²

We need to find how long it takes for the projectile to reach its maximum height

When an object reaches to its maximum height, then its velocity at this maximum height is 0

One equation of projectile is v = u + gt, where v is the final velocity, g is the acceleration of gravity, and t is the time

If the direction of motion is vertically upward, then g = -9.8 m/s²

∵ The projectile is thrown directly upward at a velocity of 12 m/s

∴ u = 12 m/s and g = -9.8 m/s²

∵ It reaches its maximum height

∴ v = 0 m/s

- Substitute these values in the rule above

∴ 0 = 12 - 9.8 t

- Add 9.8 t from both sides

∴ 9.8 t = 12

- Divide both sides by 9.8

∴ t = 1.22 seconds

It takes 1.22 s for the projectile to reach its maximum height

Learn more:

You can learn more about equations of free fall in brainly.com/question/4460262

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Step-by-step explanation:

Data given

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Wehre

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The correlation coefficient is given by:

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$r=\frac{7(30095)-(4210)(49)}{\sqrt{[7(2595100) -(4210)^2][7(354) -(49)^2]}}=0.7503$

The determination coefficient is given by:

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