If a diameter intersects a chord of a circle at a right angle, what conclusion can be made?
2 answers:
Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
You might be interested in
Answer:
Step-by-step explanation:
To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x),
c(g(x))=4(x^{2} +5x)-2
c(g(x))4+20x-2