Answer:
Options (3), (4) and (5)
Step-by-step explanation:
1). a² - 9a + 7ab + 63b
= a(a - 9) + 7b(a + 9)
Now we can not solve this problem further.
Therefore, can't be factored by grouping.
2). 3a + 4ab - b - 12
= a(3 + 4b) - 1(b - 12)
We can't solve it further.
Therefore, can't be factored by grouping.
3). ab + 6b - 2a - 12
= b(a + 6) - 2(a + 6)
= (b - 2)(a + 6)
We can be factored this expression by grouping.
4). x³ + 9x²+ 7x + 63
= x²(x + 9) + 7(x + 9)
= (x² + 7)(x + 9)
Therefore, the given expression can be factored by grouping.
5). ay² + a - y² - 1
= a(y² + 1) - 1(y² + 1)
= (a - 1)(y² + 1)
This expression can be factored by the grouping method.
Options (3), (4) and (5) are the correct answers.
Answer:
B. 8x^2-6x-7
Step-by-step explanation:
All you have to do is combine the like terms.
Like terms are the terms that have the same variable and same exponent.
The like terms in this equation are 6x^2 and 2x^2, 11x and -17x, and -3 and -4.
When you add 6x^2 and 2x^2, you get 8x^2
When you add 11x and -17x, you get -6x
When you add -3 and -4, you get -7.
Putting these all in order, your answer is
8x^2 - 6x - 7
Answer:
k=17
Step-by-step explanation:
Given F(x)=2x+3 shifts 10 units when it is replaced with the graph f(x)=2x-k.
The method to solve this kind of questions is find where the graph meets the x axis then add ten units to it .The obtained x coordinate is the point where the second graph meets the x axis.
Now first find where the F(x)=2x+3 meets the x axis by substituting F(x)=0.
Now add 10 to this x coordinate , we get x1=
=
this is x coordinate where the second line meets the x-axis.
The second line is F(x)=2x-k.
now f(x)=0 and x=17/2
On substitution we get 
k=17
