Question

suppose that consumer usage time of computers in the public library is uniformly distributed with a minimum of 20 minutes and a maximum of 80 minutes. what is the standard deviation of the distribution

Answer 1

Answer:

17.32 minutes

Step-by-step explanation:

The standard deviation for a uniform distribution is:

$\sigma =\frac{b-a}{\sqrt12}$

If a = 20 minutes and b = 80 minutes, the standard deviation is:

$\sigma =\frac{80-20}{\sqrt12} \\\sigma=17.32\ minutes$

The standard deviation of the distribution of consumer usage time of computers in the public library is 17.32 minutes.