13 !!
52/13 = 4
91/13 = 7
Good Day !!
Liaaam66
Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
the answer is a repeating decimal 31.1111111111 but just put 31.1
Let x be the first odd number.
Second odd number will be x+2
Proof:
If 3 (was) the first odd number, 3+2 would be the next which is 5.
So,
(x) (x+2) = 99
xsquare + 2x = 99
xsquare +2x - 99 = 0
xsquare +11x - 9x -99 = 0
x(x +11) -9(x + 11) = 0
(x+11) (x-9) = 0
So the two odd numbers were 9 and 11
Answer:
D.Every problem needs an equation in order to be able to solve it