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3 years ago

Write the equation of the circle. A with a center A(-4,-3) and radius 5

Mathematics

1 answer:

tiny-mole [99]3 years ago

4 0

Answer:

(x+4)^2 + (y+3)^2 = 5^2

Step-by-step explanation:

The equation of a circle is

(x-h)^2 + (y-k)^2 = r^2

now substitute the known values

(x+4)^2 + (y+3)^2 = 5^2

and theres your equation

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

2 years ago

What is the answer for the following equation?<br><br>53 x 65 + 36 ÷ 5 = ?<br>

svet-max [94.6K]

Answer:

3452.2

Step-by-step explanation:

3452.2

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2 years ago

Solve this inequality for x. 81-1 1/5 x <55

katen-ka-za [31]

Answer:

A. x > 21 2/3

Step-by-step explanation:

x is greater than 21 and two thirds

i did the math :]

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2 years ago