k = 5
the equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
To obtain this form use the method of completing the square
Since the coefficient of the x² term is 1 then
add/ subtract (half the coefficient of the x-term )² to x² - 6x
f(x) = x² + 2(- 3)x + 9 - 9 + 14 = (x - 3)² + 5 → k = 5
Answer:
1: AAS, RQC 2: ASA, SRP
Step-by-step explanation:
(1) We are shown that two angles and one side are congruent in the order of AAS. Make sure you write the letters in terms of the corresponding angles. The angles and sides are congruent because the problem labels it for us. For example, B,A,C=R,Q,S. Answers: AAS, RQC.
(2) We are shown that two angles and one side are congruent in the order of ASA. Make sure you write the letters in terms of the corresponding angles again. For example, P,Q,R=P,S,R. The angles are congruent because the problem labels it for us. Side PR is congruent to side PR by reflexive property. Answers: ASA, SRP.
I hope this helped :) Good luck
Answer:
14.5
Step-by-step explanation:
The pythagoreom theorum shows a^2 + b^2 = c^2. Therefore, c^2 - a^2 = b^2
256 - 44.89 = 211.11
The square root of 211.11 rounded to the first decimal place is 14.5
Answer:
x=6
Step-by-step explanation:
x + 5x - 3 = 39
6x - 3 = 39
6x = 36
x = 6
Yes, No, Yes, Yes, No. You fill in (x,y) numbers into the equations and if it cancels out into 4, it would be 4=4. If it doesn’t become 4=4, it’s no.
