Answer:
Initial volume of the container (V1) = 1.27 L (Approx)
Explanation:
Given:
Number of mol (n1) = 5.67 x 10⁻²
Number of mol (n2) = (5.67 +2.95) x 10⁻² = 8.62 x 10⁻²
New volume (V2) = 1.93 L
Find:
Initial volume of the container (V1)
Computation:
Using Avogadro's law
V1 / n1 = V2 / n2
V1 / 5.67 x 10⁻² = 1.93 / 8.62 x 10⁻²
V1 = 10.9431 / 8.62
Initial volume of the container (V1) = 1.2695
Initial volume of the container (V1) = 1.27 L (Approx)
Explanation:
The given reaction is redox reaction but not combustion reaction.
Redox reaction : It is a chemical reaction in which oxidation and reduction occurs simultaneously.Oxidation is gaining of electrons and reduction is loosing of electrons.
oxidation
reduction
Potassium when reacts with water ,gives potassium ion in aqueous medium and combines with hydroxide ion present in water to form potassium hydroxide where as 
ions of water by gaining electrons (from potassium in water) gives hydrogen gas.
Hence , yes it is a redox reaction
Combustion reaction are the chemical reaction in which one reactant react with oxygen molecule to give heat and light.
Here in given reaction no oxygen molecule is appearing on reactant side.
Hence not a combustion reaction.
Answer:
7.93 × 10⁻¹³ km/s
Explanation:
Step 1: Given data
Rate of growth of the fingernails (r): 2.50 cm/year
Step 2: Convert "r" from cm/year to km/year
We will use the following conversion factors.
Step 3: Convert "r" from km/year to km/s
We will use the following conversion factors.
2.50 cm/year is equal to 7.93 × 10⁻¹³ kilometers/second.
Answer:
Explanation
=============
One
=============
Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + H2O
Focus on the NO3. This is an odd problem and you usually do not focus on the complex ion. But this one works easiest if you do.
The problem now is going to be the oxygens. There are 2 with the Calcium and only 1 free one going to the water. (The NO3 has been taken care of in the last step).
Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O
Count the atoms. I think this equation is balanced.
atom Left Right Result
Ca 1 1 Balanced
O 8 8 Balanced
H 2 + 2 2*2 Balanced
N 2 2 Balanced
===========
Two
===========
CH4 + O2====> CO2 + H2O
Start with the hydrogens.
The right side requires a 2
CH4 + O2 ===> CO2 + 2H2O
Now look at the oxygens. There are 4 on the right. and only 2 on the left. You need to multiply O2 by 2
CH4 + 2O2 ===> CO2 + 2H2O
Each side has 1 Carbon 4 hydrogens and 4 oxygens. The equation is balanced.
Answer:
45.2g produce x mole of CH4. we are given the mass of methane. mass (CH4)=45.2g. molar mass (CH4) = 12+4 =16g/mol. Mole=mass. molar mass. mole=45.2. 16. mole=2.8mol. therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol
Explanation:
45.2g produce x mole of CH4. we are given the mass of methane. mass (CH4)=45.2g. molar mass (CH4) = 12+4 =16g/mol. Mole=mass. molar mass. mole=45.2. 16. mole=2.8mol. therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol
