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2 years ago

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A cylindrical oil storage tank has a height of 10 meters and a diameter of 24 meters. If the tank is full, how much oil does it

contain? Round to the nearest tenth of a kiloliter (1 m3 = 1 kL). Use 3.14 for π.

1 answer:

Fantom [35]2 years ago

8 0

For this case what you should do is find the volume of the tank in the form of a cylinder.
By definition, the volume of a cylinder is:
V = pi * (r ^ 2) * (h)
Where,
h: height
r: radio
Substituting the values we have:
V = 3.14 * ((24/2) ^ 2) * (10)
V = 4521.6 kL
Answer:
If the tank is full, it does contain 4521.6 kL of oil

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2 years ago

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Answer:

g(x) = 3(x-9)(x-5)

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Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

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$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$g(x) = 3x^{2} - 42a + 135$

So

$a = 3, b = -42, c = 135$

$\bigtriangleup = (-42)^{2} - 4*3*135 = 144$

$x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9$

$x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5$

So

g(x) = 3(x-9)(x-5)

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2 years ago

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Zolol [24]

Answer:

2nd option

Step-by-step explanation:

the equation of a circle in standard form is

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the centre is at the midpoint of the endpoints of the diameter.

The coordinates of the centre is the average of the coordinates of the endpoints.

centre = ( $\frac{-4+2}{2}$ , $\frac{7-1}{2}$ ) = ( $\frac{-2}{2}$ , $\frac{6}{2}$ ) = (- 1, 3 )

the radius is the distance from the centre to either of the endpoints

using the distance formula to calculate r

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= $\sqrt{3^2+16}$

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= $\sqrt{25}$

= 5

then equation of circle is

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(x + 1)² + (y - 3)² = 25

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