5x-8y=1...(1)
3x+6y=-21...(2)
(1)*3:
15x-24y=3...(3)
(2)*5:
15x+30y=-105...(2)
(3)-(2):
15x-24y-(15x+30y)=3-(-105)
15x-24y-15x-30y=108
-54y=108
y=-2
Answer:
<h2>
$26.25</h2>
<em><u>Solving steps:</u></em>
<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>
<em>Find: </em><em> </em><u>How much money did Sam have in his pocket?.</u>
<em>Solution:</em><em> </em>Let the equation be
<h3><em>=> P = T </em><em>+</em><em>F</em></h3>
<u>p represent amount of money</u>
<u>p represent amount of moneyt represent total</u>
<u>p represent amount of moneyt represent totalf represent money found</u>
<h3>
<em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>
<u>insert the values</u>
<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>
add<u> 19.75 from 6.50 </u>
<h3><em>=> P = </em><em> </em><em>26.25</em></h3>
<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>
In the given figure, there are two right angled triangles.
Area of triangle = 1/2 × b × h
Area of shaded region = area of larger triangle - area of smaller triangle
= 1/2 × 15 × 18 - 1/2 × 8 × 9
= 135 - 36
= 99 ft^2
Thus, area of shaded region is 99 ft^2.
Answer:divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
Step-by-step explanation:
divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.