Answer:
because it has lighter molecules.
The mass of Ba(IO3)2 that can be dissolved in 500 ml of water at 25 degrees celcius is 2.82 g
<h3>What mass of Ba(IO3)2 can be dissolved in 500 ml of water at 25 degrees celcius?</h3>
The Ksp of Ba(IO3)2 = 1.57 × 10^-9
Molar mass of Ba(IO3)2 = 487 g/mol?
Dissociation of Ba(IO3)2 produces 3 moles of ions as follows:
moles of Ba(IO3)2 = 1.16 × 10^-3 × 0.5 = 0.58 × 10^-3 moles
mass of Ba(IO3)2 = 0.58 × 10^-3 moles × 487 = 2.82 g
Therefore, mass Ba(IO3)2 that can be dissolved in 500 ml of water at 25 degrees celcius is 2.82 g.
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There you go try that out.
The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
N = ?
T = 449 K
V = 58.35 L
P =2.97
R = 0.082
Use the clapeyron equation:
P x V = n x R x T
2.97 x 58.35 = n x 0.082 x 449
173.2995 = n x 36.818
n = 173.2995 / 36.818
n = 4.70 moles
hope this helps!