Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type possible genotypes
Type A AA, AO
Type B BB, BO
Type AB AB
Type O OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired homozygous smooth haired
P gen SS x ss
F1 gen. Ss
phenotype: wire haired
B. carbohydrate
C6H12O6 is the formula for sugar, and sugar is a carbohydrate.
Answer:
It is important to have more than one piece of evidence to make sure that the evidence is actually evidence. Or in other words, that the evidence is proven true. With only one piece of evidence, you can't be fully sure if calculations were correct, if the source was trustworthy, etc.
Multiple evidence is kinda like double checking math problems. If you don't do it, you can't be 100% certain the answer is correct.
Explanation:
Because there's a higher concentration of oxygen molecules outside the cell compared to the cell's cytoplasm, you'll see that oxygen diffuses into the cell along this concentration gradient. ... Because the molecules are moving at random, some will move out of the cell, but most will be moving in in this case.
