Answer:
speed=d/t
let him cover x distance while walking
running d=4.5-x
s1=x/0.5 km/hr....(1)
s2=4.5-x//5/12.....(2)
atq.....s2=2+s1
s1=2x
s2=54-12x/5
by eqn 1 and 2
s1+s2=2x+54-12x/5
putting value of s2
s1+2+s1=2x+54-12x/5....taking LCM =5
10s1+10= 10x+54-12x
as s1=2x
10s1+10= -2x+54
10s1+10=-s1+54
11s1=44
speed when walking=4km/hr
Answer:
I usually use this graphing calculator to graph:
www . desmos . com / calculator
<span>it false ......................</span>
Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)
Therefore, function 1 has the least minimum value at (-1, -3)
If the question is 5m^2 the answer is 80. And if the question is 5m2 then it is 40
