What is the slope of the line that contains the points (3,1) and (2,-3)

1 answer:

8 0

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-1}{2-3}\implies \cfrac{-4}{-1}\implies 4$

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