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3 years ago

Write a fourth grade word problem where the answer is 35.

Mathematics

2 answers:

rusak2 [61]3 years ago

7 0

Answer:

Step-by-step explanation:

15+14+6

15+14= 29

29+6= 35

masya89 [10]3 years ago

7 0

Answer:

Sarah has 7 folders to separate work given from 7 different classes. If Sarah is given 5 pieces of paper from each class, how much paper is that in total?

Step-by-step explanation:

That would be a total of 35 pieces of paper. This is because 7*5 is equal to 35.

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A check is _____.

torisob [31]

Answer:

Step-by-step explanation:

A check is an I.O.U. or a promissory note.

3 0

2 years ago

Read 2 more answers

PLEASE HELP ME IM STRUGGLING!!!

Kitty [74]

Answer:

The required answer is $c=7\sqrt{3}$

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

$\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\$

Substituting the values we get

$\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}$

$\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7$

Now in Triangle ADC Tangent identity we have

$\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}$

Substituting the values we get

$\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}$

The required answer is $c=7\sqrt{3}$

8 0

2 years ago

For each ordered pair (x, y), determine whether it is a solution to the inequality 4x+8y5-8. Is it a solution? Yes No O (6, – 4)

avanturin [10]

Given inequality is:

$4x+8y\leq-8$

Now for (6,-4), Put x=6 nd y=-4 in given inequality:

$\begin{gathered} 4(6)+8(-4)\leq-8 \\ 24-32\leq-8 \\ -8\leq-8 \end{gathered}$

So for (6,-4) this inequality is true.

For (-2,-3) put x=-2 and y=-3 in given inequality:

$\begin{gathered} 4(-2)+8(-3)\leq-8 \\ -8-24\leq-8 \\ -32\leq-8 \end{gathered}$

As -32 is less than -8 then this condition is also true.

simillarly you can check for other options also.

For (-7,5) Put x=-7 and y=5 in given inequality:

$\begin{gathered} 4(-7)+8(5)\leq-8 \\ -28+40\leq-8 \\ 12\leq-8 \end{gathered}$

As 12 is grater than -8 so this condition is false.

And for (-6,0) put x=-6 and y=0 in given inequality:

$\begin{gathered} 4(-6)+8(0)\leq-8 \\ -24\leq-8 \end{gathered}$

As -24 is less than -8 so it is true.

4 0

9 months ago

Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr

mixer [17]

Answer:

A . 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

<u>Oliver's Interviewees</u>

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

$\frac{70}{100} * \frac{176}{1}$

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

$\frac{30}{100} * \frac{176}{1}$

Cross multiply

52.8 were 9th-graders interviewed by Oliver

<u>Jenny's Interviewees</u>

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

$\frac{75}{100} * \frac{140}{1}$

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

$\frac{25}{100} * \frac{140}{1}$

Cross multiply

35 students were 10th-graders interviewed by Jenney.

<u />

<u>Total calculation</u>

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

<h2>Therefore, there are 36 more 10th than 9th.</h2>

<u />

<h3><u>Extra Info:</u></h3>

<u>Oliver's Interviewees Percentage</u>

Since we are given 30% of the 9th-grade class and 70% of the 10th-grade class, first, let's add the percentages. To do so, set it up as a fraction;

30% = $\frac{30}{100}$ while, 70% = $\frac{70}{100}$

Now solve it;

$\frac{30}{100} + \frac{70}{100}$

Simplify; cancel bottom zero's;

$\frac{30}{1} + \frac{70}{1}$

Add the remaining numerators;

30 + 70 = 100

Which is 100%

<u>Jenny's Interviewees Percentage</u>

Since we're given 75% of the 9th-grade class and 25% of the 10th-grade, it will end up the same answer. I'll show you how; first, let's add the percentages. To do so, set it up as a fraction;

25% = $\frac{25}{100}$ and, 75% = $\frac{75}{100}$