If the answer is not C D then is A bc of the way it crosses over
According to the statement we can deduce that the resulting amplitude of the wave pulse is zero when there is a destructive interference of two pulses and the chain is straight. At this point the potential energy will be zero, therefore when applying the energy conservation theorem, the potential energy must be equal to the kinetic energy and be conserved. The potential energy will be totally transferred as kinetic energy and therefore that will be the only energy present in the string.
Thus, the option C is correct.
<span>First lets determine the equation. Well at the top of the circle both the normal force and the weight are in the same direction. So we have Fnet=N+mg. Since this is a circular path the Fnet is also = to (mv^2)/r.
We convert the situation where the rock is no longer in contact with the bottom to terms relevant to the equation. So, what is a requirement for normal force? The object must be in contact with the surface, meaning it can't be in free fall. Realizing this means that the instant when the object does not touch the bucket is where the normal force = 0.
Now we have N+mg=(mv^2)/r where N=0 is the case we are interested in. This leaves 0+mg=(mv^2)/r
Solve for v:
v=(gr)^(1/2) or v=3.28m/s
</span>
Answer:
208.08 pounds
Explanation:
Given that,
Mass of a man, m = 75.5 kg
Starting from rest, the elevator ascends, attaining its maximum speed of 1.65 m/s in 0.675 s.
We need to find the value of spring scale during these 0.675 s.
As the elevator ascends, net force will be given by :
F = mg + ma
a can be calculated as follows :
So,
F = 75.5[(9.81) + (2.45)]
F = 925.63 N
We know that,
1 N = 0.224 Pounds
It means, 925.63 N = 208.08 pounds
So, the spring scale will register 208.08 pounds.
i dont know but hey Explanationh:
