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3 years ago

12

How many times does the image of the octagon coincide with the preimage during the rotation?

2 answers:

Delicious77 [7]3 years ago

7 0

The image would coincide with the pre-image during the rotation. Therefore, the octagon would coincide a total of 8 times as it rotates 360 degrees about its center.

Dennis_Churaev [7]3 years ago

4 0

An octagon has 8 sides, a rotation of 45° (360°/8) will map the octagon onto its preimage. Answer is 8.

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S.ubscribe to Seedator on youtu.be

natulia [17]

Answer:

lol okay

Step-by-step explanation:

7 0

2 years ago

What is wrong with the following equation?x2+xâˆ’20/xâˆ’4=x+5a. (xâˆ’4)(xâˆ’5)â‰ x2+xâˆ’20b. The left-hand side is not defined f

joja [24]

Answer:

The answer to this question can be defined as follows:

In part (i), the answer is "option d".

In part (ii), the answer is "option 2".

Step-by-step explanation:

Given:

Part (a)

$\Rightarrow \bold{\frac{x^2+x-20}{x-4}=x+5}\\\\$

Solve the above equation:

$\Rightarrow x^2+x-20=(x+5)(x-4)\\\\\Rightarrow x^2+x-20=(x^2-4x+5x-20)\\\\\Rightarrow x^2+x-20=x^2-4x+5x-20\\\\\Rightarrow \boxed{x^2+x-20=x^2+x-20}\\$

Given:

Part (b)

$\Rightarrow \bold{ \lim_{x \to \3} \frac{x^2+x-12}{x-3}= \lim_{x \to 3} (x+4)}\\\\$

Solve the above equation:

factor of $\Rightarrow x^2+x-20 =(x-3)(x+4)$

$\Rightarrow \lim_{x \to \3} \frac{(x-3)(x+4)}{x-3}= \lim_{x \to 3} (x+4)\\\\\Rightarrow \lim_{x \to \3} (x+4)= \lim_{x \to 3} (x+4)\\\\$

apply limit value:

$\Rightarrow (3+4)= (3+4)\\\\\Rightarrow 7= 7$

6 0

2 years ago

Write the definition of unit rate:<br> 16 pointssssss

ivolga24 [154]

Answer:

it is a special type of ratio. It will compare 1 unit of some quantity to a different number of units of a different quantity

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Tell whether the angles are complementary or supplementary. Then find the value of x.

fredd [130]

Answer:

complementary, x=60

Step-by-step explanation:

complementary angles add up to 90 degrees.

90= x + x- 30

2x= 120

x= 60

6 0

2 years ago

Read 2 more answers

In a geometric series, the first term is 108 and the common ratio is \frac{2}{3}. Find the sum of the first 8 terms.

Valentin [98]

Answer:

311.36

Step-by-step explanation:

For a geometric series sum of first n terms is $a(1-r^n)/(1-r)$

if r is less than 1.

where a is the first term and r is the common ratio.

____________________________\

given

a = 108

r = $\frac{2}{3}.$

n = 8

thus , sum of n term is

$a(1-r^n)/(1-r)\\=>108(1-(2/3)^8)/(1-2/3)\\=> 108 (1 - 256/6561)/1/3\\=> 108(6561-256)/ 6561/1/3\\=> 108(6305)/2187\\=>311.36$

Thus sum of first 8 terms is 311.36

7 0

2 years ago