This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
Answer:
This would be non linear
Step-by-step explanation:
Because a linear is a straight line
this would not equal to a straight line so it is non linear
have a nice day uvu
The letter C, because the pattern is this (I think):
Every two letters it states the vowels (a,e,i,o,u)
Then in between every two letters there starts a pattern of, saying the alphabet in order and saying the alphabet backwards.
In other words they merged these two lines:
A, B, C, D, E...
+
Z, Y, X, W, V...
=
A, Z, B, Y, C, X...etc.
then by adding this pattern of vowels you get:
A, Z, E, B, I, Y, O, (C), (U), (X)...
2p*p= 2p^2 because when you multiply p by p it squares it, then you keep the 2 in front of it
