Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Required experession is g(5000) = 50
Y=1/2x+8
Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
Hey there! Sorry no one is answering! Definitely B!!
Answer:
(2,5)
Step-by-step explanation:
Keep in mind that clockwise is towards the right in this problem. We are moving the point from quadrant 2 to quadrant 1.
Draw a picture for yourself to help this make sense. Put the point, then just turn your whole paper 90 degrees to the right. This is your new point!