We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
c = AC
b = BC
a = AB
AC² = AB² + BC² , substitute values we have:
2² = 1² + BC²
BC² = 4-1
BC = √3
BC = 1.732
The answer for the length of BC is 1.732 units.
Answer:
the answer is x=-1
Step-by-step explanation:
Answer:
45
Step-by-step explanation:
The first part of the question is to throw you off and is of no use
To find the answer you must find the midpoint of 30 and 60
which shall give you 45 and that is the answer to the question
Hope this helped you
Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then
has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.