The mean radius of the sun is 432,450 miles (696,000 kilometers), which makes its diameter about 864,938 miles (1.392 million km). You could line up 109 Earths across the face of the sun. The sun's circumference is about 2,713,406 miles (4,366,813 km). The total volume of the sun is 1.4 x 1027 cubic meters.

3 0

2 years ago

The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m

monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

= 130 x $10^{-12}$ m

The diameter of a vanadium atom = 2 x radius

= 2 x 130 x $10^{-12}$

= 260 x $10^{-12}$ m

Given a distance of 1.30 mm = 1.30 x $10^{-3}$ m,

The number of vanadium atoms required to span the distance = $\frac{1.3*10^{-3} }{260*10^{-12} }$

= 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0

2 years ago

1. Sulfuric acid is formed when sulfur dioxide gas reacts with oxygen gas and water. Write a balanced chemical equation for the

tekilochka [14]

Answer:

1. Balanced chemical for the given chemical reaction is :

$2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow 2H_2SO_4(aq)$

number of mole of sulphuric acid produced = 12.5 mol

number of mole of oxygen required=6.25 mol

Explanation:

1. Balanced chemical for the given chemical reaction is :

$2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow 2H_2SO_4(aq)$

from above balanced equation it is clearly that ,

2 mole of sulpher dioxide gives 2 mole of sulphuric acid

1 mole of sulpher dioxide gives 1 mole of sulphuric acid

therefore,

12 .5 mole of sulpher dioxide will givs 12.5 mole of sulphuric acid

number of mole of sulphuric acid produced = 12.5 mol

2 mole of sulphur dioxide needs 1 mole of oxygen gas

so,

1 mole of sulphur dioxide needs 0.5 mole of oxygen gas

therefore 12.5 of sulphur dioxide needs $12.5 \times 0.5$ mole of oxygen

number of mole of oxygen required=6.25 mol

4 0

2 years ago