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Svetradugi [14.3K]

2 years ago

13

PLZ HELP ME SCHOOL IS RIGHT AROUND THE CORNER

2 answers:

Jobisdone [24]2 years ago

5 0

Rice vinegar is 1.5 units out of 1.5 + 5 = 6.5 units of vinegar. So in 17 ounces of the mixture, the amount of rice vinegar will be

$\dfrac{1.5}{6.5} \cdot 17 = 3.923...$

Answer: 3.9 ounces of rice vinegar

AnnZ [28]2 years ago

3 0

Quantity of rice vinegar= one and half parts of total

Quantity of cide vinegar = 5 parts of total

ratio of rice vinegar : cide vinegar = 1.5 :5

total quantity = 17 ounces

$quantity of rice vinegar = \frac{1.5}{6.5} * 17$

Quantity of rice vinegar = 3.92 ounces

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I need help please!!!

e-lub [12.9K]

There is no distinct pattern, the scatter plot would be up down and spread apart, nothing really correlated.

3 0

1 year ago

The coordinates of the endpoint of QS are Q(-9,8) and S(9,-4). Point R is on cue as such that QR:RS Is in the ratio 1:2. What ar

marishachu [46]

R(–3, 4)

Step-by-step explanation:

Let Q(-9,8) and S(9,-4) be the given points and let R(x, y) divides QS in the ratio 1:2.

By section formula,

$R(x, y)=R\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)$

Here, $x_{1}=-9, y_{1}=8, \text { and } x_{2}=9, y_{2}=-4 \text { and } m=1, n=2$

Substituting this in the section formula

$R(x, y)=R\left(\frac{1(9)+2(-9)}{1+2}, \frac{1(-4)+2(8)}{1+2}\right)$

To simplifying the expression, we get

$\Rightarrow R(x, y)=R\left(\frac{9-18}{3}, \frac{-4+16}{3}\right)$

$\Rightarrow R(x, y)=R\left(\frac{-9}{3}, \frac{12}{3}\right)$

⇒ R(x,y) = R(–3,4)

Hence, the coordinates of point R is (–3, 4).

6 0

2 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

2 years ago

A rational number between -2/3 and 1/4 is

Eduardwww [97]

Answer:

-7/12 is the answer of your question

6 0

2 years ago

Read 2 more answers

The slope of the function on the left is multiplied by p, and q is added to the y-intercept to arrive at the function on the rig

Marizza181 [45]

Answer:

the answer is C

Step-by-step explanation:

plato

5 0

2 years ago