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2 years ago

Calculate the wavelengths of the first five emission lines of the Balmer series for hydrogen

Physics

1 answer:

In-s [12.5K]2 years ago

5 0

Answer:

Explanation:

The Balmer series in a hydrogen atom relates the possible electron transitions down to the n = 2 position to the wavelength of the emission that scientists observe. In quantum physics, when electrons transition between different energy levels around the atom (described by the principal quantum number, n) they either release or absorb a photon. The Balmer series describes the transitions from higher energy levels to the second energy level and the wavelengths of the emitted photons. You can calculate this using the Rydberg formula.

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insens350 [35]

Answer:

$-\frac{1}{2}$

Diverging lens

Explanation:

Given parameters:

Power of lens = -2.0D

Unknown:

Focal length = ?

Solution:

The power of lens is the reciprocal of the focal length;

P = $\frac{1}{f}$

where f is the focal length

f = $\frac{1}{P}$ = $-\frac{1}{2}$

The lens is a diverging lens

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2 years ago

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2 years ago

Read 2 more answers

675 km equals how much cm ?

irga5000 [103]

KHDMDCM.
Now go from Kilometer to Centimeter: 5.
Move the decimal 5 places to the right: 67,500,000 centimeters.
Hope this helps :)

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2 years ago

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galina1969 [7]

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1 year ago