What are the zeros of 3x²(x+π)³(x-4)²
1 answer:
Hi again!
The zeros are the values of x. This is where the graph intersects the x - axis. In order to find the zeros, replace y with 0 and solve for x.
The answer is x = 0, -π, 4
I am not sure what grade are you or the level, but for me, they sometimes asked me to find their multiplicities as well
The multiplicity of a root is the number of times the root appears.
So, the answer are
x = 0 and the multiplicity of 2
x = -π and the multiplicity of 3
x = 4 and the multiplicity of 2
Good luck with your studies!
The zeros are the values of x. This is where the graph intersects the x - axis. In order to find the zeros, replace y with 0 and solve for x.
The answer is x = 0, -π, 4
I am not sure what grade are you or the level, but for me, they sometimes asked me to find their multiplicities as well
The multiplicity of a root is the number of times the root appears.
So, the answer are
x = 0 and the multiplicity of 2
x = -π and the multiplicity of 3
x = 4 and the multiplicity of 2
Good luck with your studies!
You might be interested in
My triangle solver says EF ≈ 7.5 ft.
_____
The law of cosines is usually used for this.
EF^2 = DE^2 +DF^2 -2*DE*DF*cos(D)
.. = 6^2 +11^2 -2*6*11*cos(40°)
.. ≈ 55.88
EF ≈ √55.88 ≈ 7.5 . . . ft
_____
The law of cosines is usually used for this.
EF^2 = DE^2 +DF^2 -2*DE*DF*cos(D)
.. = 6^2 +11^2 -2*6*11*cos(40°)
.. ≈ 55.88
EF ≈ √55.88 ≈ 7.5 . . . ft