Question

How do I solve: 6x^2 -x-12=0 ^2 means squared by the way!

Answer 1

$6x^2 -x-12=0\\ 6x^2+8x-9x-12=0\\ 2x(3x+4)-3(3x+4)=0\\ (2x-3)(3x+4)=0\\ x=\frac{3}{2} \vee x=-\frac{4}{3}$