<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = </h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is=
=
= = 54 square units
The length of AC =
=
= units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔ units
Therefore the perpendicular distance from B to AC is =
0 or 1 or more than one for zero functions
So 30/48=15/(x+9)
this could be easily solved by recognizing the proportion (the other way is usiing full algebra and doing multiply both sides by 48(x+9) and then divide both sides by 30 then subtract 9)
30 is 2 times of 15
therefor 48 is 2 times of (x+9)
48=2 times (x+9)
divide both sides by 2
24=x+9
subtract 9
15=x
x=15
Step-by-step explanation:
his mistake was that he didnt follow the rules of the order of operations and he multiplied 4 by 4 and just added the third power and the 6th power getting the wrong answer
hope this helps:) good luck