Answer:
80.386 degrees
Explanation:
We use the cosine equation here (which is the adjacent side of the unknown angle divided by the hypotenuse
The adjacent side = 699ft
The hypotenuse = 1034ft
using cos∅ = Adjacent/hypotenuse
where ∅ is the unknown angle
cos ∅ = 699/1034 = 0.167
∅ = arccos 0.167 = 80.368°
As easy as one can imagine
I know for a fact the answer is D. the distance traveled by the wave during one full cycle
Hi there!
A.
Since the can was launched from ground level, we know that its trajectory forms a symmetrical, parabolic shape. In other words, the time taken for the can to reach the top is the same as the time it takes to fall down.
Thus, the time to its highest point:
Now, we can determine the velocity at which the can was launched at using the following equation:
In this instance, we are going to look at the VERTICAL component of the velocity, since at the top of the trajectory, the vertical velocity = 0 m/s.
Therefore:
***vsinθ is the vertical component of the velocity.
Solve for 'v':
Now, recall that:
Plug in the expression for velocity:
B.
We can use the same process as above, where T' = 2T and Th = T.
C.
The work done in part B is 4 times greater than the work done in part A.
Answer:
Explanation:
same idea as before Liam, first, find the parallel resistance in 35 || 20
(35*20) / (35+20) = 700 / 55 = 12.727272 ohms
now add the 12.727272 + 15 = 27.727272 ohms total resistance
V = IR
10 = I * 27.727272
10 / 27.727272 = I
0.360655 = I
V = IR (again, but across the 15 ohm resistor)
V = 0.360655 * 15
V = 5.4098