Moles of glucose = Molarity x volume solution
= 4.5 x 1.5
= 6.75 moles.
Hope this helps, have a great day ahead!
D. this is the correct answer because the question is showing a comparison of sizes rather than the actual sizes which eliminates B. A and C have no relevance.
Because the concentration of molecules in the gas phase increases with increasing pressure, the concentration of dissolved gas molecules in the solution at equilibrium is also higher at higher pressures
