A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12
b.) The y-intercept is 12
c.) The y-intercept represent the height of the ball at time t = 0
d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
Answer: x ≤3
Step-by-step explanation:
Your answer is correct
Answer:
46
Step-by-step explanation:
Well $1o each than 10×4=40 and 40 +6=46
: Let y = f(x) = x^1/3
Then dy = 1/3*x^(−2/3) dx
Since f(64) = 4.
We take x = 64 and dx = ∆x = 1
This gives dy = 1/3*(64)^(−2/3)* (1) = 1/48
∴65^(1/3) = f(64 + 1) ≈ f(64) + dy = 4 + 1/48 ≈ 4.021 <span>
</span>
Answer:
Step-by-step explanation:
Given that ∆KLM ~ ∆RSK, 
(similarity theorem)
KL = 65
KR = 65 - 52 = 13
KM = 60
KS = ?
Cross multiply
