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2 years ago

Please help me this is due today

Mathematics

1 answer:

Evgen [1.6K]2 years ago

6 0

Split the room into 2 rectangles
area = 5*4 + 3*3 = 29 sq ft

So the cost is 29*8 = $232

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A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

8 0

3 years ago

A hiker averages 1.4 mph downhill on a mountain trail and 0.8 mph uphill. Find the total time spent hiking in terms of the dista

nadya68 [22]

Answer:

V=d/t.

V=(1.4)(0.8)÷8m/s

=0.14

Step-by-step explanation:

bali yung divide ay guhit sa baba

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2 years ago

x can do a job in 16 days and y can do the same jovb in 20 days x y and z can do the job in 7.5 days. alone z can do the same jo

MissTica

Answer:

24 days

Step-by-step explanation:

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2 years ago

Read 2 more answers

Write an equation in slope intercept form y-intercept 4 and slope is -3/5

dusya [7]

$\bf y=-\cfrac{3}{5}x+4\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

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2 years ago

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uranmaximum [27]

Answer: 10,000

Step-by-step explanation:

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2 years ago