Answer:
1st pic) 17.8
2nd pic) 16.8
3rd pic) 9.1
4th pic) 13.5
Step-by-step explanation:
<u>1st pic:</u>
(write equation) Cos 27 (cos 27 = 0.89) =
(new equation) 0. 89 =
(multiply 20 on both sides) 0.89 x 20 = x 20
(solve) 17.8 = x
<u>2nd pic:</u>
(write equation) tan 40 (tan 40 = 0.84) =
(new equation) 0.84 =
(multiply 32 on both sides) 0.84 x 20 = x 20
(solve) 16.8 = x
<u>3rd pic:</u>
(write equation) cos 55 (cos 55 = 0.57) =
(new equation) 0.57 =
(multiply 16 on both sides) 0.57 x 16 = x 16
(solve) 9.1 = x
<u>4th pic:</u>
(write eqaution) tan 42 (tan 42 = 0.90) =
(new equation) 0.90 =
(multiply 15 on both sides) 0.90 x 15 = x 15
(solve) 13.5 = x
Given data:
The first equation is 3j +14=-5z.
The second equation is -10j=5z .
Add both the equations.
Substitute 2 for j in the first equation.
Thus, the value of j is 2 and z is -4.
Simplify the experssion and you get 10.
Hope this helps!
-5y + 8 = -3y + 10
We need to get y on one side.
Add 3y to both sides.
-2y + 8 = 10
We need to get 2y by itself.
Subtract 8 from both sides.
-2y = 2
Divide both sides by -2 to solve for y.
y = -1
I hope this helps!
We are given 2 sides 18.7, 16.1 and a NON-included angle.
We have to calculate the altitude of the triangle.
altitude = 18.7 * sine (35)
altitude = 18.7 * 0.57358
altitude =
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10.725946
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In this case, side c is greater than the altitude and is less than side a so 2 two triangles will be formed.
Source:
http://www.1728.org/trigssa.htm