Answer:
a) T = 2.26 N, b) v = 1.68 m / s
Explanation:
We use Newton's second law
Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string
sin 30 =
cos 30 =
Tₓ = T sin 30
T_y = T cos 30
Y axis
T_y -W = 0
T cos 30 = mg (1)
X axis
Tₓ = m a
they relate it is centripetal
a = v² / r
we substitute
T sin 30 = m (2)
a) we substitute in 1
T =
T =
T = 2.26 N
b) from equation 2
v² =
If we know the length of the string
sin 30 = r / L
r = L sin 30
we substitute
v² =
v² =
For the problem let us take L = 1 m
let's calculate
v =
v = 1.68 m / s
Complete Question:
Given at a point. What is the force per unit area at this point acting normal to the surface with ? Are there any shear stresses acting on this surface?
Answer:
Force per unit area,
There are shear stresses acting on the surface since
Explanation:
equation of the normal,
Traction vector on n,
To get the Force per unit area acting normal to the surface, find the dot product of the traction vector and the normal.
If the shear stress, , is calculated and it is not equal to zero, this means there are shear stresses.
Since , there are shear stresses acting on the surface.
Answer:
Adding heat makes the particles move faster so the particles have more kinetic energy when more thermal energy is added
Explanation: