Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
Answer:
Step-by-step explanation:
You have to use the discriminant for this. If the quadratic is 
, then
a = -4, b = -3, and c = 7. The formula for finding the discriminant is
which comes from the quadratic formula, but without the square root sign. Filling in:
which simplifies down to
D = 9 + 112 so
D = 121. This is a perfect square, so the solutions will be 2 real. Just so you know, you will NEVER have a solution like the one offered in the third choice down. If you have one imaginary root, you will ALWAYS have a second by the conjugate rule.
In the 8th row there’s a Q and if u go sideways down it’s quadrilateral if u need more lmk!
Answer: 20x^3 - 23x^2 - 4x + 4
Explanation:
Use distributive property:
(5x-2)(4x^2 - 3x-2)
= 20x^3 - 15x^2 - 10x - 8x^2 + 6x + 4
= 20x^3 - 23x^2 - 4x + 4
Answer:
D
Step-by-step explanation:
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