Ok so first you need to find out how long it was so started at 4:13 ended at 4:23 thats 10 minutes. Then you need to find out how many you download at that time so 625-115= 510 the. You just divide 510 in to 10 minutes so the answer is 51. Hope I helped:)
Answer:
n = 2
Step-by-step explanation:
0.5n - 2 - 3 = 3 - 2n -3
0.5n + 2n = 2 + 3 + 3 -3
2.5n = 5
n = 2
Answer:
0.60
Step-by-step explanation:
In the category of pets
22 students had a cat = P(C)
17 students had a dog = P(D)
9 students had both a dog and a cat = P(C and D)
The formula to find the Probability of two events =
P(C or D) = P(C) + P(D) - P(C and D)
P(cat or dog) = P(cat) + P( dog) - P(cat and dog)
P(cat or dog) = 22/50 + 17/50 - 9/50
P(cat or dog) = 0.44 + 0.34 - 0.18
P(cat or dog) = 0.60
The probability the student will have a dog or a cat is 0.60
Answer: I couldn't solve due to the way you worded it this so I looked it up and got m,24. I don't believe that is the answer..but if you can message me wording it properly I can most definitely solve it for you. :)
Answer:
you have to divide the total cost by the amount of lunches bought so that equation would be 185÷25. according to my calculator that would be seven dollars and forty cents or $7.40
