Answer:
This is an improper fraction so we need to make it a mix fraction.
Step-by-step explanation:
21/10 = 10/10+10/10+1/10
10/10=1
So your final answer will be
Answer:
A
Step-by-step explanation:
Since we're dealing with perpendicular lines, we take the recipricol of the m value of the original equation.
So the slope we're dealing with is 1/2.
And the equation we have so far is
y = 1/2x + b
Now we solve for b by plugging in the point (4,2).
2 = 1/2(4) + b
2 = 2 + b
b = 0
So the final equation is
y = 1/2x
The answer is 6. 8-6(6) = -28.
Look at the graph below carefully
Observe the results of shifting ={2}^{x}f(x)=2x
vertically:
The domain, (−∞,∞) remains unchanged.
When the function is shifted up 3 units to ={2}^{x}+3g(x)=2x +3:
The y-intercept shifts up 3 units to (0,4).
The asymptote shifts up 3 units to y=3y=3.
The range becomes (3,∞).
When the function is shifted down 3 units to ={2}^{x}-3h(x)=2 x −3:
The y-intercept shifts down 3 units to (0,−2).
The asymptote also shifts down 3 units to y=-3y=−3.
The range becomes (−3,∞).
Given:
The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).
To find:
The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.
Solution:
If a figure reflected across the line x=a, then
The triangle after a reflection over x = -3. So, the rule of reflection is
The vertices of triangle after reflection are
Similarly,
And,
Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).