Which of the following has the least value?
2 answers:
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Answer:
21
Step-by-step explanation:
Note that n! = n(n - 1)(n - 2) ..... × 3 × 2 × 1, thus
7! = 7 × 6 × 5 × 4 × 3 × 2 × 1
5! = 5 × 4 × 3 × 2 × 1
2! = 2 × 1
Hence
cancel 5 × 4 × 3 × 2 × 1 on numerator/ denominator, leaving
=
= 21