A segment is bounded by two endpoints.
The two segments can have up to two common points
Assume the line segments are AB and CD where the length of AB is greater than the length of CD.
<u>The possibilities are:</u>
- <em>A point of segment CD lies on segment AB</em>
- <em>Both points of segment CD lie on segment AB.</em>
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See attachment for both possibilities.
Hence, it is possible for the two segments to have two common points.
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Answer: number 1 2 and four are correct
Step-by-step explanation:
I DID THE SAME THING
Answer: Triangle ABC and Triangle ECD
Step-by-step explanation:
In Triangle ABC and Triangle ECD
BD=CD and AD=ED [given in the figure]
∠BDA=∠EDC [Vertically opposite angles are equal]
⇒ΔABC ≅ ΔECD [By SAS postulate]
SAS postulate or Side Angle Side postulate tells that if two sides and their included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
Answer: 0.27648
Step-by-step explanation:
Given : The proportion of all individuals have group A blood : p=0.040
Total individuals give blood : n= 6
Let X be the number of individuals have group A blood.
Since all individual are independent of each other.
Formula : , where n= sample size , p = probability of getting success in each trial.
The probability that exactly three of the individuals have group A blood. :
The probability that exactly three of the individuals have group A blood. is 0.27648