Write the formula for compound formed between pb^2+O^2
1 answer:
You might be interested in
Answer:
The molarity of the base is 0.2664 M
Explanation:
Firstly, we write the complete and balanced titration reaction.
+
→
+
From the reaction, we can identify that 1 mole of the acid reacted with 2 moles of the alkali (base) to yield salt and water only
We identify the following also from the question;
= 14.80 mL ,
= 25.00 mL ,
= 0.225M and
= ?
= 1 ,
= 2
We use the relation;
/
=
/
Plugging the values, we have ;
(0.225 × 14.80)/1 = ( × 25.00)/2
= (2 × 0.225 × 14.80)/25
= 0.2664 M
Answer:
See explanation
Explanation:
I have attempted to show the sequence of the reaction between carbamic acid and ammonia to form an amide and water and urea.
The reaction first involves the protonation of ammonia to give ammonium carbamate.
When ammonium carbamate is heated to 130-140 degrees, we obtain urea and water as the final products of the reaction
