Sorry i cant even read that
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
I'm not sure about part 1, you may need to google it, but part two is 11 protons, 11 electrons and 12 neutrons. You can find protons and electrons by just looking at the atomic number, and you can find neutrons by subtracting the atomic number from the atomic mass.
Answer:
<h3>C. hot air rising and cooler air failing. </h3>
Explanation:
<h3>Please mark my answer as a brainliest. That is the correct answer. ❤❤❤❤</h3>
1 mole ----------- 6.02x10²³ molecules
? moles --------- 1.9x10²⁵ molecules
moles = 1.9 x 10²⁵ * 1 / 6.02x10²³
= 1.9 x 10²⁵ / 6.02x10²³
= 31.561 moles
hope this helps!