Perpendicular lines have slopes that multiply to get -1
y=mx+b is the slope intercept equation
m=slope
so get into y=mx+b form
-x+2y=4
solve for y
add x both sides
2y=x+4
divide by 2 both sides
y=(1/2)x+2
the slope is 1/2
perppendicular line slope multiplies to -1
1/2 times what=-1
times 2/1 both sides
what=-2/1=-2
y=-2x+b
find b
we are given a point is (-2,1)
when x=-2, y=1
1=-2(-2)+b
1=4+b
minus 3 both sides
-3=b
so the equation is
y=-2x-3
your teacher might want it in standard form (ax+by=c) so
add 2x both sides
2x+y=-3 is an equation
so y=-2x-3 is correct (slope intercept form)
2x+y=-3 is also correct (standard form)
Answer:
x = 4 ±
Step-by-step explanation:
Given
(x - 12)(x + 4) = 9 ← expand the left side using FOIL
x² - 8x - 48 = 9 ( ad 48 to both sides )
x² - 8x = 57
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 4)x + 16 = 57 + 16
(x - 4)² = 73 ( take the square root of both sides )
x - 4 = ± ( add 4 to both sides )
x = 4 ±
Answer:
Step-by-step explanation:
Is 359’000
That’s what it should be
Hey there!
<h2>
ANSWER: </h2><h2>
EXPLANATION:</h2>
Ratio of
If you want to get the ratio, you should multiply the numerator(7) and denominator(3) by 2.
So your answer is:
Hope this helps!
<u>Answer-</u>
<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>
<u>Solution-</u>
The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.
For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.
Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)
If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.
Applying distance formula we get,
As,
Therefore, the vertex at K (-4, 8) is the orthocentre.