Answer:A. Both animals and plants have changed over time.
Explanation:
Because plants and animals go through adaptations.
Answer: The molar mass of each gas
Explanation:
Mole fraction is the ratio of moles of that component to the total moles of solution. Moles of solute is the ratio of given mass to the molar mass.
Suppose if there are three gases A, B and C.
a)
b)
c)
moles of solute =
Thus if mass of each gas is known , we must know the molar mass of each gas to know the moles of each gas.
Answer:
4.6L
Explanation:
Use the equation (P1*V1)/(T1)=(P2*V2)/(T2)
P= pressure
V= volume
T= temperature in kelvins (remember K= C + 273)
Convert atm to mmHg or vise versa
1.5atm*(760mmhg/1atm)= 1140mmHg
(733mmHg * 5.36L)/(298K)=(1140mmHg * V)/(402K)
V= 4.6 or 4.65L (depending on sig figs)
Answer:
The percent isotopic abundance of Ir-193 is 60.85 %
The percent isotopic abundance of Ir-191 is 39.15 %
Explanation:
we know there are two naturally occurring isotopes of iridium, Ir-191 and Ir-193
First of all we will set the fraction for both isotopes
X for the isotopes having mass 193
1-x for isotopes having mass 191
The average atomic mass is 192.217
we will use the following equation,
193x + 191(1-x) = 192.217
193x + 191 - 191x = 192.217
193x- 191x = 192.217 - 191
2x = 1.217
x= 1.217/2
x= 0.6085
0.6085 × 100 = 60.85 %
60.85% is abundance of Ir-193 because we solve the fraction x.
now we will calculate the abundance of Ir-191.
(1-x)
1-0.6085 =0.3915
0.3915× 100= 39.15 %